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10x^2-35x-245=0
a = 10; b = -35; c = -245;
Δ = b2-4ac
Δ = -352-4·10·(-245)
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11025}=105$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-105}{2*10}=\frac{-70}{20} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+105}{2*10}=\frac{140}{20} =7 $
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